Question:

How many atoms of gold are in 2.3 grams of gold?

Solution:

Atoms of gold in 2.3 grams of Gold

Molecular Weight (Molar mass)

Molecular weight or molar mass is the amount of mass of a substance for each mole (or) mass of the example(sample) containing 6.023 X 10²³ atoms or molecules.

Avogadro’s Number

We can utilize Avogadro’s number to change over among mass and the quantity of moles of any unadulterated substance.

It is the quantity of particles present in 1 mole of a substance
It is roughly 6.023 X 10²³ particles for every mole.

Gold:

• Symbol – Au
• Atomic number – 79
• Mass number (Molar Mass) – 196.967 g mol^-1

Number of moles calculator:

Molar mass of the substance (Au) M = 196.967 g mol^-1 Mass of the substance (Au) m = 2.3 g (given) Quantity of substance (mole ) n = m/M

mole n = mass/molecular weight mole n = 2.3 g/196.967 g mol^-1

n = 0.012 mole

Number of atoms calculator:

Number of atoms = Number of moles X Avogadro number

= 0.012 X 6.023 X 10²³

= 7.227 X 10²¹

Total number of atoms of gold in 2.3 g of gold:

• Number of atoms of gold are in 2.3 grams of gold is = 7.227 X 10²¹