Solution:

Initial velocity of the racing car u=0 (since the car was initially at rest)

Time taken (t) =10 second

Acceleration of the racing car (a) =4 ms^-2

Distance covered by the car =?

Let us substitute the above values in the following equation of motion

$$s=ut+\frac{1}{2} a t^2$$

$$s=0(10)+\frac{1}{2}4(10^2)$$

$$s=200 m$$

Therefore the distance covered by the racing car in 10 s is 200 m