Catégorie : CBSE & NEET PHYSICS

Solution: Initial velocity of the racing car u=0 (since the car was initially at rest) Time taken (t) =10 second Acceleration of the racing car (a) =4 ms-2 Distance covered by the car =? Let us substitute the above values in the following equation of motion $$s=ut+\frac{1}{2} a t^2$$ $$s=0(10)+\frac{1}{2}4(10^2)$$ $$s=200 m$$ Therefore the distance…