Question: A particle covers 3/4 th of total distance with speed v1 and next 1/4 th with speed v2. Find the average speed of the particle. Solution: $$Average \ speed = \frac{Total \ distance}{Total \ time \ taken}$$ Total distance is $${\frac{3}{4}(d)+\frac {1}{4}(d) =d}$$ Let the speed be v1 for the 3/4 th distance and…