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Étiquette : GRADE 11 PHYSICS
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Calculating Car Acceleration and Displacement in 3rd Second
Question: A car moving in a straight line at 30 ms-1 slows uniformly to a speed of 10 ms-1 in 5 sec.Determine the Solution: (a) Acceleration of the car Initial velocity of the car u=30 ms-1 Final velocity of the car v=10 ms-1 Time taken t = 5 sec $${Acceleration =\frac{change \ in \ velocity}{time…
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Calculating Car Retardation and Stopping Time in Physics | Explanation
Question: A car moving along a straight highway with speed of 126 Kmh-1 is brought to a stop within a distance of 200 m. What is the retardation of the car (assumed uniform), and how long does it take for the car to stop? Solution: Initial velocity of the car u =126 Kmh-1 Converting the…
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Ball Thrown Upward: Motion Analysis and Calculations
Question: A player throws a ball upwards with an initial speed of 29.4 ms-1 . Solution: Upward direction: Position-Positive Velocity-negative Acceleration-positive Downward direction: Position-positive velocity – positive Acceleration-positive $${u=gt}$$ $${t=\frac {u}{g}}$$ $${t=\frac{29.4}{9.8}}$$ $${t= 3\sec}$$ Total time taken =Time taken to reach top +Time taken to reach the bottom $${3 \ s +3 \ s =6…
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Motion Under Gravity: Key Concepts and Calculations
Question: A ball thrown up from the ground reaches a maximum height of 20 m. Find Solution: (a) Its initial velocity $${u=\sqrt{2gh}}$$ $${u=\sqrt {(2)(10)(20)}}$$ $${u=\sqrt 400 =20 \frac{m}{s}}$$ Its initial velocity is 20 ms-1 (b). The time taken to reach the maximum height $${u=gt}$$ $${t=\frac{u}{g}}$$ $${t=\frac {20}{10}}$$ $${t=2 s}$$ The time taken to reach maximum…
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Motion Under Gravity Numerical: Calculating Ball’s Speed at Point C
Question: A ball is thrown vertically upwards with an initial velocity of 5 ms-1 from point A as shown below. C is a point 10 m vertically below the point A. The the speed of the ball at point C will be(take g=10 ms-2 and neglect air resistance) Solution: Initial velocity u= +5 ms-1 (From…