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Question: An anti-aircraft shell is fired vertically upwards with a muzzle velocity of 294 ms-1.Calculate Solution: (1) Anti-aircraft shell-Maximum height Condition for maximum height(H) is $${\sin^2\theta=1}$$ $${H=\frac{u^2}{2g}=\frac{294^2}{2(9.8)}}$$ $${H=(15)(294)=4410 \ m =4.41 \ Km}$$ (2) Time taken to reach maximum height Time taken to reach maximum height is $${t=\frac{u}{g}=\frac{294}{9.8}=30 \ s}$$ (3) Velocity at the end…
This blogpost breaks down the concept of average speed,revealing the straightforward relationship between distance, time and velocity.Forget complex equations; We’ll guide you through practical examples to master this fundamental principle of motion.
Question: A driver applies brakes on seeing a traffic signal 400 m ahead. At the time of applying the brakes the vehicle was moving with a speed of 15 ms-1 and retarding with 0.3 ms-2 .What is the distance of the vehicle after one minute from the traffic signal? Solution- Braking distance Time taken for…
Question: A stone is thrown upwards with a speed v from the top of a tower.It reaches the ground with a speed 3v.What is the height of the tower? Solution: Thrown up – Sign convention Tower height calculation: Applying third equation of motion $${v^2=u^2+2as}$$ Here initial velocity u=+v Final velocity v= -3v Acceleration due to…
Question: A stone is thrown vertically upwards with a velocity of 19.6 ms-1 . After 2 seconds, another stone is thrown upwards with a velocity of 9.8 ms-1 .When and where will these stones collide? Solution: First Stone: Time taken by the first stone to reach its maximum height when thrown with an initial speed…