🔥 NEET Physics: Thermodynamics Practice Q&A

50 MCQs with Answers & Explanations | +4/-1 Pattern

Q1

First law of thermodynamics is based on:

A. Conservation of mass
B. Conservation of energy
C. Conservation of momentum
D. Conservation of charge
✅ Show Answer & Explanation

Answer: B. Conservation of energy
Explanation: First law of thermodynamics is the law of conservation of energy for thermodynamic systems: ΔU = Q - W.

Q2

Which thermodynamic process occurs at constant temperature?

A. Isobaric
B. Isochoric
C. Isothermal
D. Adiabatic
✅ Show Answer & Explanation

Answer: C. Isothermal
Explanation: Isothermal process occurs at constant temperature (ΔT = 0).

Q3

In an isochoric process, work done is:

A. Maximum
B. Minimum
C. Positive
D. Zero
✅ Show Answer & Explanation

Answer: D. Zero
Explanation: In isochoric process, volume is constant, so dV = 0, hence work W = ∫PdV = 0.

Q4

The internal energy of an ideal gas depends only on:

A. Pressure
B. Volume
C. Temperature
D. Density
✅ Show Answer & Explanation

Answer: C. Temperature
Explanation: For an ideal gas, internal energy depends only on temperature (U = nCvT).

Q5

The ratio of specific heats Cp/Cv for monatomic gas is:

A. 5/3
B. 7/5
C. 4/3
D. 3/2
✅ Show Answer & Explanation

Answer: A. 5/3
Explanation: For monatomic gas, γ = Cp/Cv = 5/3 ≈ 1.67.

Q6

Second law of thermodynamics states that:

A. Energy cannot be created or destroyed
B. Entropy of the universe increases
C. Heat flows from cold to hot body
D. Pressure is constant
✅ Show Answer & Explanation

Answer: B. Entropy of the universe increases
Explanation: Second law: For any spontaneous process, the total entropy of the universe always increases.

Q7

In an adiabatic process:

A. ΔQ = 0
B. ΔT = 0
C. ΔP = 0
D. ΔV = 0
✅ Show Answer & Explanation

Answer: A. ΔQ = 0
Explanation: Adiabatic process has no heat exchange with surroundings (Q = 0).

Q8

The efficiency of a Carnot engine depends on:

A. Working substance
B. Temperatures of source and sink
C. Pressure of the gas
D. Volume of the gas
✅ Show Answer & Explanation

Answer: B. Temperatures of source and sink
Explanation: Carnot efficiency η = 1 - T₂/T₁, depends only on temperatures.

Q9

The zeroth law of thermodynamics leads to the concept of:

A. Internal energy
B. Entropy
C. Temperature
D. Enthalpy
✅ Show Answer & Explanation

Answer: C. Temperature
Explanation: Zeroth law establishes the concept of temperature and thermal equilibrium.

Q10

For an isothermal expansion of an ideal gas:

A. ΔU = 0
B. ΔU > 0
C. ΔU < 0
D. ΔU = Q
✅ Show Answer & Explanation

Answer: A. ΔU = 0
Explanation: For isothermal process, temperature constant → internal energy constant (ΔU = 0).

Q11

The value of Cp - Cv for an ideal gas is:

A. R
B. nR
C. R/2
D. 2R
✅ Show Answer & Explanation

Answer: A. R
Explanation: For an ideal gas, Cp - Cv = R (molar specific heats).

Q12

In a cyclic process, the net change in internal energy is:

A. Positive
B. Negative
C. Zero
D. Maximum
✅ Show Answer & Explanation

Answer: C. Zero
Explanation: In cyclic process, system returns to initial state, so ΔU = 0.

Q13

The entropy of a system increases in:

A. Reversible process
B. Irreversible process
C. Isothermal process
D. Adiabatic process
✅ Show Answer & Explanation

Answer: B. Irreversible process
Explanation: Entropy increases in irreversible (spontaneous) processes.

Q14

The efficiency of a heat engine can never be:

A. 0%
B. 50%
C. 100%
D. 75%
✅ Show Answer & Explanation

Answer: C. 100%
Explanation: According to second law, efficiency of a heat engine cannot be 100% (cannot convert all heat into work).

Q15

In an adiabatic compression, the temperature of the gas:

A. Increases
B. Decreases
C. Remains constant
D. Becomes zero
✅ Show Answer & Explanation

Answer: A. Increases
Explanation: In adiabatic compression, work is done on the gas, increasing its internal energy and temperature.

Q16

The specific heat of a gas at constant pressure is greater than that at constant volume because:

A. Work is done by the gas
B. Volume remains constant
C. Pressure remains constant
D. Temperature increases
✅ Show Answer & Explanation

Answer: A. Work is done by the gas
Explanation: At constant pressure, gas expands doing work, requiring additional heat energy.

Q17

The working of a refrigerator is based on:

A. First law of thermodynamics
B. Second law of thermodynamics
C. Zeroth law of thermodynamics
D. Third law of thermodynamics
✅ Show Answer & Explanation

Answer: B. Second law of thermodynamics
Explanation: Refrigerator transfers heat from cold to hot body by doing work, following second law (Clausius statement).

Q18

For a diatomic gas, the value of γ = Cp/Cv is:

A. 5/3
B. 7/5
C. 4/3
D. 3/2
✅ Show Answer & Explanation

Answer: B. 7/5
Explanation: For diatomic gas, γ = 7/5 = 1.4.

Q19

The area under P-V diagram represents:

A. Heat
B. Work
C. Internal energy
D. Entropy
✅ Show Answer & Explanation

Answer: B. Work
Explanation: Work done = ∫P dV, which is the area under the P-V curve.

Q20

The process that occurs without exchange of heat with surroundings is called:

A. Isothermal
B. Isobaric
C. Adiabatic
D. Isochoric
✅ Show Answer & Explanation

Answer: C. Adiabatic
Explanation: Adiabatic process has Q = 0, no heat exchange.

Q21

The internal energy of an ideal gas is a function of:

A. Pressure only
B. Volume only
C. Temperature only
D. Pressure and volume
✅ Show Answer & Explanation

Answer: C. Temperature only
Explanation: For ideal gas, U depends only on temperature (U = nCvT).

Q22

A Carnot engine works between 27°C and 127°C. Its efficiency is:

A. 20%
B. 25%
C. 75%
D. 33.3%
✅ Show Answer & Explanation

Answer: B. 25%
Explanation: η = 1 - T₂/T₁ = 1 - (300/400) = 1 - 0.75 = 0.25 = 25%.

Q23

The temperature at which a real gas behaves ideally is:

A. Critical temperature
B. Boyle temperature
C. Inversion temperature
D. Triple point
✅ Show Answer & Explanation

Answer: B. Boyle temperature
Explanation: At Boyle temperature, a real gas obeys Boyle's law and behaves ideally.

Q24

The change in entropy for a reversible isothermal process is:

A. ΔS = Q/T
B. ΔS = 0
C. ΔS = nR ln(V₂/V₁)
D. Both A and C
✅ Show Answer & Explanation

Answer: D. Both A and C
Explanation: For isothermal process, ΔS = Q/T = nR ln(V₂/V₁).

Q25

The coefficient of performance of a refrigerator is given by:

A. Q₂/W
B. W/Q₂
C. Q₁/W
D. W/Q₁
✅ Show Answer & Explanation

Answer: A. Q₂/W
Explanation: COP = Heat extracted from cold body / Work input = Q₂/W.

Q26

For an ideal gas undergoing isothermal expansion, the internal energy:

A. Increases
B. Decreases
C. Remains constant
D. First increases then decreases
✅ Show Answer & Explanation

Answer: C. Remains constant
Explanation: Isothermal means constant temperature, and U depends only on T for ideal gas.

Q27

The equation PV^γ = constant holds for:

A. Isothermal process
B. Isobaric process
C. Adiabatic process
D. Isochoric process
✅ Show Answer & Explanation

Answer: C. Adiabatic process
Explanation: For reversible adiabatic process, PV^γ = constant, where γ = Cp/Cv.

Q28

The total entropy of the universe:

A. Always decreases
B. Always increases
C. Remains constant
D. Can increase or decrease
✅ Show Answer & Explanation

Answer: B. Always increases
Explanation: According to second law, total entropy of the universe always increases for spontaneous processes.

Q29

The value of universal gas constant R is:

A. 8.314 J/mol·K
B. 1.38 × 10⁻²³ J/K
C. 6.022 × 10²³ mol⁻¹
D. 9.8 m/s²
✅ Show Answer & Explanation

Answer: A. 8.314 J/mol·K
Explanation: Universal gas constant R = 8.314 J/(mol·K) = 2 cal/(mol·K).

Q30

Which of the following is NOT a state function?

A. Internal energy
B. Entropy
C. Heat
D. Enthalpy
✅ Show Answer & Explanation

Answer: C. Heat
Explanation: Heat and work are path functions, not state functions.

Q31

The triple point of water occurs at:

A. 0°C, 1 atm
B. 0.01°C, 4.58 mm Hg
C. 100°C, 1 atm
D. -273°C, 0 atm
✅ Show Answer & Explanation

Answer: B. 0.01°C, 4.58 mm Hg
Explanation: Triple point of water is 273.16 K (0.01°C) at 4.58 mm Hg pressure.

Q32

In a free expansion of an ideal gas:

A. Temperature decreases
B. Temperature increases
C. Temperature remains constant
D. Pressure increases
✅ Show Answer & Explanation

Answer: C. Temperature remains constant
Explanation: For free expansion of ideal gas, no work is done and no heat exchange, so ΔU = 0 → ΔT = 0.

Q33

The latent heat of vaporization of water is approximately:

A. 80 cal/g
B. 540 cal/g
C. 1 cal/g
D. 4.18 J/g
✅ Show Answer & Explanation

Answer: B. 540 cal/g
Explanation: Latent heat of vaporization of water is 540 cal/g (2260 kJ/kg).

Q34

The efficiency of a Carnot engine operating between 100°C and 25°C is:

A. 20%
B. 75%
C. 25%
D. 33.3%
✅ Show Answer & Explanation

Answer: A. 20%
Explanation: η = 1 - (298/373) = 1 - 0.799 = 0.201 ≈ 20%.

Q35

The specific heat of water is:

A. 1 cal/g°C
B. 4.18 J/g°C
C. Both A and B
D. Neither A nor B
✅ Show Answer & Explanation

Answer: C. Both A and B
Explanation: Specific heat of water is 1 cal/g°C = 4.18 J/g°C.

Q36

The process in which no heat enters or leaves the system is called:

A. Isothermal
B. Adiabatic
C. Isobaric
D. Isochoric
✅ Show Answer & Explanation

Answer: B. Adiabatic
Explanation: Adiabatic process has Q = 0.

Q37

The root mean square speed of gas molecules is proportional to:

A. √T
B. T
C. 1/√T
D. T²
✅ Show Answer & Explanation

Answer: A. √T
Explanation: vrms = √(3RT/M) → vrms ∝ √T.

Q38

The ideal gas equation is:

A. PV = nRT
B. PV = RT
C. PV = kT
D. PV = NkT
✅ Show Answer & Explanation

Answer: A. PV = nRT
Explanation: Ideal gas equation: PV = nRT, where n is number of moles.

Q39

The average kinetic energy of a gas molecule is:

A. (1/2)kT
B. (3/2)kT
C. (5/2)kT
D. kT
✅ Show Answer & Explanation

Answer: B. (3/2)kT
Explanation: Average KE per molecule = (3/2)kT, where k is Boltzmann constant.

Q40

The temperature at which the volume of a gas becomes zero is:

A. 0°C
B. 273 K
C. -273°C
D. 100 K
✅ Show Answer & Explanation

Answer: C. -273°C
Explanation: Absolute zero (-273.15°C or 0 K) is the theoretical temperature where gas volume becomes zero.

Q41

The degree of freedom for a monatomic gas is:

A. 5
B. 3
C. 6
D. 2
✅ Show Answer & Explanation

Answer: B. 3
Explanation: Monatomic gas has 3 translational degrees of freedom.

Q42

Which law states that entropy of a pure crystalline substance at absolute zero is zero?

A. First law
B. Second law
C. Third law
D. Zeroth law
✅ Show Answer & Explanation

Answer: C. Third law
Explanation: Third law of thermodynamics states entropy of a perfect crystal at absolute zero is zero.

Q43

The work done in an isochoric process is:

A. Positive
B. Negative
C. Zero
D. Maximum
✅ Show Answer & Explanation

Answer: C. Zero
Explanation: W = ∫P dV, and dV = 0 in isochoric process, so work = 0.

Q44

In an isobaric process, the heat supplied is used for:

A. Increasing internal energy only
B. Doing work only
C. Both increasing internal energy and doing work
D. Neither
✅ Show Answer & Explanation

Answer: C. Both increasing internal energy and doing work
Explanation: Q = ΔU + W, so heat increases internal energy and does work.

Q45

The value of Boltzmann constant k is:

A. 1.38 × 10⁻²³ J/K
B. 8.314 J/mol·K
C. 6.022 × 10²³ mol⁻¹
D. 9.8 m/s²
✅ Show Answer & Explanation

Answer: A. 1.38 × 10⁻²³ J/K
Explanation: Boltzmann constant k = R/NA = 1.38 × 10⁻²³ J/K.

Q46

For an adiabatic process, which of the following is constant?

A. PV
B. PV^γ
C. P/V
D. V/T
✅ Show Answer & Explanation

Answer: B. PV^γ
Explanation: For reversible adiabatic process, PV^γ = constant.

Q47

The molar specific heat at constant pressure Cp for monatomic gas is:

A. (3/2)R
B. (5/2)R
C. (7/2)R
D. R
✅ Show Answer & Explanation

Answer: B. (5/2)R
Explanation: For monatomic gas, Cv = (3/2)R, Cp = Cv + R = (5/2)R.

Q48

Which of the following is an example of irreversible process?

A. Slow compression of gas
B. Free expansion of gas
C. Quasi-static process
D. Reversible isothermal expansion
✅ Show Answer & Explanation

Answer: B. Free expansion of gas
Explanation: Free expansion is irreversible as it cannot be reversed without external work.

Q49

The enthalpy change for a process is given by:

A. ΔH = ΔU + PΔV
B. ΔH = ΔU - PΔV
C. ΔH = Q + W
D. ΔH = ΔU
✅ Show Answer & Explanation

Answer: A. ΔH = ΔU + PΔV
Explanation: Enthalpy H = U + PV, so ΔH = ΔU + PΔV + VΔP. At constant pressure, ΔH = ΔU + PΔV.

Q50

The maximum efficiency of a heat engine working between 300 K and 600 K is:

A. 100%
B. 75%
C. 50%
D. 25%
✅ Show Answer & Explanation

Answer: C. 50%
Explanation: η_max = 1 - T₂/T₁ = 1 - 300/600 = 1 - 0.5 = 0.5 = 50%.

📝 Key Thermodynamics Formulae

ΔU = Q - W η = 1 - T₂/T₁ PV = nRT Cp - Cv = R ΔS = Q/T PV^γ = constant

📚 Complete Set of 50 Thermodynamics Questions
All questions with answers and explanations for NEET preparation

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