Circular Motion — Class 11 Physics
Class 11 Physics

Circular Motion

The complete visual guide — from zero to NEET-ready. Concepts, formulas, practice, and exam strategy all in one place.

⚛ CBSE Board 🎯 NEET / JEE ✓ NCERT Aligned

Concepts from Zero

Start here. Build the intuition before memorizing formulas.

🔵
What is Circular Motion?

When an object moves along a circular path, it's in circular motion. The key insight — even if speed is constant, direction keeps changing.

Core Insight: Changing direction = changing velocity. Changing velocity = acceleration. Acceleration needs a force. That force is Centripetal Force — always pointing inward toward the centre.
⚡ Uniform Circular Motion
Speed = constant
Direction = changing
Velocity = changing
|a| = constant
e.g. Earth around Sun
🎢 Non-Uniform Circular Motion
Speed = changing
Direction = changing
Both v and a change
|a| varies
e.g. Roller coaster loop
💡
Build Intuition — Step by Step
📐
Core Concepts Deep Dive 🔥 High Weight
1
Angular Velocity (ω) ω = Δθ / Δt  |  Unit: rad/s How fast the angle is changing. Think of it as "rotational speed."
2
Linear ↔ Angular Speed v = rω Outer edge of a spinning disc moves faster than the inner edge — same ω, bigger r, bigger v!
3
Centripetal Acceleration Exam Fav a = v²/r = rω² Always points towards the centre. It's what keeps bending the path into a circle. Without it, the object flies off tangentially.
4
Centripetal Force F = mv²/r = mrω²
NOT a new force! It's whatever existing force points inward:
🪨 Stone on string → Tension  |  🚗 Car on road → Friction  |  🌍 Planet → Gravity
5
Time Period & Frequency T = 2π/ω = 2πr/v    f = 1/T = ω/2π T = time for one complete revolution. f = revolutions per second (Hz).

Live Visualizer

Interact with the simulation to see velocity and acceleration in real time.

v (m/s)
—
a=v²/r
—
ω rad/s
—
Speed 1.5
Radius 120
Show / Hide
Observe: Blue (v) is always tangent. Red (a) always points inward. They are always 90° apart.
Increase radius → same ω, more linear speed (v = rω)
Increase speed → more centripetal acceleration (a = v²/r)
📌
Direction Rules — Board Style
Circular motion vector directions O (centre) r 90° Velocity (v) Tangent to circle — tries to escape Acceleration (a) Always → centre (centripetal) Angle between v and a Always 90° — perpendicular always! v a

Formula Sheet

Every formula you need — with units and when to use each.

∑
Core Formulas 🔥 Memorise
v = rω
Linear ↔ Angular speed
a = v²/r
Centripetal acceleration
a = rω²
Centripetal acc (angular)
F = mv²/r
Centripetal force
F = mrω²
Centripetal force (angular)
T = 2π/ω
Time period from ω
T = 2πr/v
Time period from v
f = 1/T
Frequency (Hz)
ω = 2πf
Angular ↔ Frequency
ω = 2π/T
Angular ↔ Period
📊
Units & When to Use
QuantitySymbolUnitWhen to use
Angular velocityωrad/sRPM or revolutions given
Linear velocityvm/sSpeed in m/s given directly
Centripetal acc.am/s²Find force or check circular condition
Centripetal forceFN (Newton)Tension, friction, gravity problems
Time periodTsecondsTime for one full revolution given
FrequencyfHz (hertz)Revolutions per second given
🎯
Problem Solving — 5 Step Strategy NCERT
1
Identify — Is this circular motion? Uniform or non-uniform? What is the radius?
2
Find Radius — Length of string, radius of road curve, orbit radius, or half-diameter.
3
Choose Formula — v given → use a = v²/r. ω given → use a = rω² and v = rω first.
4
Identify Inward Force — Tension? Friction? Normal force component? Gravitational pull?
5
Equate and Solve — Set that force = mv²/r. Substitute values. Solve for unknown.
💡 NEET Shortcut for RPM problems: If n RPM given → f = n/60 Hz → ω = 2πn/60 rad/s → use F = mrω²

Special Cases

High-scoring topics in CBSE and NEET — learn these deeply.

🎡
Vertical Circular Motion 🔥 NEET Favourite
A stone on a string completing vertical circles. Speed is NOT constant — gravity speeds it at bottom, slows at top.
🔻 At Bottom
Tension: T_b = mg + mv²/r
T opposes weight → T is MAXIMUM
Both T and gravity, T acts up, gravity down
🔺 At Top
Tension: T_t = mv²/r − mg
T and mg both inward → T is MINIMUM
Net inward: T + mg = mv²/r
Min speed at top (string stays taut, T = 0):
v_top_min = √(gr)
Min speed at bottom (energy conservation):
v_bot_min = √(5gr)
🛣️
Banking of Roads 🔥 CBSE Exam Must

Roads are tilted (banked) on curves so vehicles can turn safely even without friction.

tan θ = v²/rg
θ = banking angle  |  v = optimal speed  |  r = radius  |  g = 9.8 m/s²
With friction (NEET level):
v_max = √(rg × (μ + tanθ)/(1 − μtanθ))
v_min = √(rg × (tanθ − μ)/(1 + μtanθ))
🔗
Conical Pendulum ⚠ Tricky

A ball on a string moving in horizontal circles. String makes angle θ with vertical.

Vertical equilibrium
T cosθ = mg
Horizontal (centripetal)
T sinθ = mv²/r
T = 2π√(L cosθ / g)
L = string length
🏍️
Well of Death (Cylinder / Circus)

Cyclist rides inside a vertical cylinder. Normal force from wall acts as centripetal force; friction holds them up.

Condition (no sliding down):
μN ≥ mg  →  μ(mv²/r) ≥ mg
∴ v_min = √(rg/μ)

Common Mistakes

These 6 mistakes cost students the most marks. Learn the corrections.

❌ Myth: "Centripetal force is a special new force"
✅ Centripetal force is NOT a new type of force. It's the label for whatever net inward force exists in the situation — tension, friction, gravity, or normal force. Never draw it separately on a free body diagram!
❌ Myth: "Velocity points towards the centre"
✅ Velocity is always TANGENTIAL — along the tangent to the circle. Acceleration points towards the centre. Remember: velocity "wants to escape," acceleration pulls it back in.
❌ Confusing ω (rad/s) with v (m/s)
✅ They relate by v = rω. For same angular velocity ω, outer points have MORE linear speed. Always convert RPM → ω = 2πn/60 before substituting.
❌ Writing T_top = mg + mv²/r (wrong sign at top of loop)
✅ At the TOP, both tension AND gravity point inward (towards centre), so T + mg = mv²/r. This gives T = mv²/r − mg. At bottom, only T points inward while mg points outward → T − mg = mv²/r.
❌ Not converting RPM to rad/s before using formulas
✅ ω = 2πf, where f = RPM/60. So 300 RPM → f = 5 Hz → ω = 10π rad/s. Never plug RPM directly into the formula!
❌ Not knowing which force acts as centripetal force
✅ Always ask: "What force is pointing towards the centre?" Car on flat road = friction. Car on banked road = N sinθ. Planet around star = gravity. Roller coaster top = weight + Normal. Identify first, equate to mv²/r.

Practice MCQs

Attempt questions, check your score, and read explanations.

Score: 0 / 0

Quick Revision Sheet

Everything you need — one page. Study this the night before.

Core Formulas
v = rω
a = v²/r = rω²
F = mv²/r = mrω²
T = 2π/ω = 2πr/v
f = 1/T, ω = 2πf
Direction Rules
Velocity → tangent to circle
Acceleration → towards centre
v ⊥ a — always 90°
Speed = constant (UCM only)
ω = constant (UCM only)
Force Selection
String/rope → Tension
Road curve → Friction
Banked road → N sinθ
Planet/satellite → Gravity
Well of death → Normal force
Vertical Circle
T_bottom = mg + mv²/r
T_top = mv²/r − mg
v_min(top) = √(gr)
v_min(bottom) = √(5gr)
tan θ = v²/rg (banking)
The VATO Rule
V
elocity
A
lways tangent
T
owards centre = a
O
nly net inward force
Velocity → tangent  |  Acceleration → centre  |  Always 90° between them  |  Only existing inward force = centripetal
Exam Strategy — CBSE: Always draw FBD. Label all forces. Write formula. Substitute. Solve. Show every step for full marks.

Exam Strategy — NEET: Use direction logic to eliminate options instantly. If a force is shown pointing outward — eliminate. Check units match. Banking → tan θ = v²/rg. "String goes slack" → v_top = √(gr).

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