Free Body Diagrams — Complete Physics Guide
CBSE Physics · Class 11 & 12 · Complete Guide

Free Body
Diagrams

The backbone of every force problem in physics

35+
Diagrams
8
NCERT Chapters
5
Solved Examples
7
Step Method
Scroll to learn
01

NCERT Chapter Mapping

The Universal Truth

Every chapter in mechanics uses FBD. Master it once — use it everywhere, forever.

Class 11

Laws of Motion ⭐

Core concept. Newton's laws, normal force, tension. Every single problem needs FBD first.

Topics: F=ma · action-reaction · connected bodies · inertia
Class 11

Friction

FBD shows direction of friction force — the most common mistake area in all of physics.

Topics: μs · μk · angle of friction · inclined plane
Class 11

Work, Energy & Power

FBD identifies which forces do work. W = F·d·cosθ — FBD gives you the angle θ directly.

Topics: Work by gravity, normal, friction, spring
Class 11

Circular Motion

Net inward force = centripetal force. FBD identifies which forces provide this centripetal force.

Topics: Banking · conical pendulum · vertical circle
Class 12

Electrostatics

Coulomb's force, charge in field, dipole. FBD shows direction of attraction and repulsion.

Topics: Coulomb's law · electric field · dipole forces
Class 12

Moving Charges & Magnetism

Lorentz force on charges and current conductors. Right-hand rule + FBD = full solution.

Topics: Lorentz force · current in field · cyclotron
Class 12

Rotational Mechanics

Torque-based FBD. Draw forces at their exact point of application. τ = r × F.

Topics: Torque · equilibrium · rolling · MI
Exam Insight

FBD → Marks Pipeline

In board exams, drawing a correct FBD earns 1–2 marks even if the final answer is wrong. Examiners reward method over result.

No FBD drawn = Lose 30% marks on force questions
02

Concept Building

The Golden Rule — Memorize This

"Draw ALL forces acting ON the object — NOT forces the object exerts ON others."

🔍 What is a Free Body Diagram?

A Free Body Diagram (FBD) is a simple, clean drawing where you take ONE object and isolate it completely. You then replace every connection to other objects with a force arrow. The result is a picture that shows exactly what forces act on your chosen object — and nothing else.

✓ What you include
Weight (mg) always
Normal force from surfaces
Tension from strings
Friction from rough surfaces
Applied forces
✗ What you NEVER include
"Force of motion" arrow
Forces the object exerts on others
Internal forces (for whole system)
Velocity arrows
Acceleration arrows

⚡ Internal vs External Forces

External forces appear in FBD. Internal forces cancel and do NOT appear in the FBD of the whole system.

Tug of War Example:

System = both teams. External = ground friction. Internal = rope tension (cancels). For FBD of ONE person → rope tension becomes external!

🧲 Why Isolate the Body?

Physics can only analyze ONE object at a time with F = ma. Isolation ensures:

  • Clear picture of all forces
  • No confusion between action/reaction
  • Clean equations that actually solve
  • Full marks in board exams
Force Name Symbol Direction When It Acts Formula
Weight / GravityW or mgAlways ↓ (downward)Always, on every object with massmg (m×10)
Normal ForceN⊥ to surface, away from itObject touching a surfaceVaries
TensionTAlong string, away from objectConnected by string/rope/cableVaries
FrictionfOpposite to motion/tendencyObject on rough surfaceμN
Applied ForceFAs given in problemPushed or pulled externallyGiven
Spring ForceF_sOpposite to stretch/compressConnected to springkx
Electric ForceF_EAlong E for +q; opposite for −qCharged particle in electric fieldqE
Magnetic ForceF_B⊥ to both velocity and BMoving charge in magnetic fieldqvB
BuoyancyF_bAlways ↑ (upward)Object submerged in fluidρVg
03

The FBD Algorithm

Board Exam Mantra

"No FBD = No Marks." Follow these 7 steps every single time. No shortcuts.

1

Identify the Object

Choose which body you want to analyze. Circle it mentally. You can only analyze ONE body at a time (unless treating a combined system).

Example: "Block on table" → your object = the block only
2

Isolate It (Mental Cut)

Imagine cutting all strings, surfaces, and connections. Draw the object alone in the center of your paper — just a simple box or dot.

Draw a square to represent the block. No table, no surroundings, no context.
3

Add Weight First (Always!)

Weight (mg) acts on EVERY object. Draw it downward first — before any other force. This is the one you most often forget.

⚠️ Even a charged particle in space — if it has mass, mg acts on it!
4

Replace Surroundings with Forces

Everything you "cut" in Step 2 becomes a force arrow. Table removed → Normal force ↑. String removed → Tension. Ground removed → Normal force.

Ask: "What was touching the object?" Each contact → one force arrow.
5

Draw All Forces with Direction

Draw each force as an arrow starting from the object's center. Arrow length can suggest relative magnitude — longer arrow = bigger force.

Use arrows of different lengths to show relative magnitudes visually.
6

Label Every Force

Label every arrow: W or mg (weight), N (normal), T (tension), f (friction), F (applied). Add subscripts if needed: T₁, T₂, N₁, N₂.

Unlabelled arrows = 0 marks. Always write the force name next to each arrow.
7

Choose Axes & Write Equations

Choose x and y axes. For inclines, tilt axes along and perpendicular to incline. Resolve forces and write: ΣFx = max, ΣFy = may.

Pro tip: Choose axes to minimize forces that need resolving. Tilt for inclines!
04

Visual Diagram Library

1. Block on Smooth Table

Block N ↑ mg ↓ N = mg

2 forces only. N balances mg perfectly. Object at rest → N = mg.

2. Block Hanging by String

Block T ↑ mg ↓ T = mg

String pulls UP with T. Gravity pulls DOWN with mg. T = mg at rest.

3. Object in Free Fall

Object mg ↓ ⚠ ONLY 1 force! a = g = 10 m/s²

ONLY gravity acts. No normal force (not on surface). a = g downward.

4. Block Pushed (Smooth Surface)

Block N mg F → F = ma (net)

4 forces: N↑, mg↓, F→. No friction on smooth surface. F = ma.

5. Incline — No Friction

θ N mg mgsinθ N=mgcosθ · a=gsinθ

N perpendicular to incline = mgcosθ. Component along incline = mgsinθ causes acceleration.

6. Incline — With Friction

θ N mg f ↑ a = gsinθ − μgcosθ

Block slides DOWN → friction acts UP incline. a = gsinθ − μgcosθ.

7. Block Pulled UP Incline

N mg f ↓ F ↑ F−mgsinθ−f=ma

Moving UP → friction now acts DOWN the incline. F must overcome both mgsinθ AND friction.

8. Two Blocks on Incline

m₁ m₂ θ Same acceleration for both

Connected blocks on incline move together. Same acceleration. Tension is internal to system.

9. Two Blocks — Horizontal

m₁ m₂ F F−T = m₁a T = m₂a a = F/(m₁+m₂)

Draw FBD of EACH block separately. Tension T is external to each block individually.

10. Atwood Machine

pulley m₁ m₂ T↑ T↑ a=(m₂-m₁)g/(m₁+m₂)

Same tension T throughout (massless string, frictionless pulley). Draw each mass separately.

11. Table + Hanging Mass

M m N↑ T→ T↑ mg↓ a = mg/(M+m)

Horizontal block pulled by hanging mass through pulley. Same acceleration for entire system.

12. Static Friction (Not Moving)

Block N mg F f_s f_s = F (block at rest)

Static friction exactly equals applied force. f_s ≤ μ_s × N. Block stays still.

13. Limiting Friction

Block about to slide F_max μ_s·N ⚠ MAX static friction

At limiting friction — block JUST about to move. Any more force → motion begins. f_max = μ_s N.

14. Kinetic Friction (Moving)

~ ~ ~ rough surface ~ ~ ~ ~ Block → moving F f_k F−f_k = ma · f_k=μ_k·N

Kinetic friction f_k = μ_k × N. Note: μ_k is always less than μ_s!

15. Block Pressed Against Wall

Wall Block f ↑ mg↓ F← N f=mg · N=F (4 forces, equilibrium)

Wall provides normal force horizontally. Friction acts upward to balance gravity.

16. Conical Pendulum

m Tcosθ Tsinθ mg Tcosθ=mg · Tsinθ=mv²/r tanθ = v²/rg

Resolve T into vertical (balances mg) and horizontal (centripetal) components.

17. Vertical Circle — Bottom

m T ↑ mg ↓ Bottom of circle T−mg = mv²/r T = mg + mv²/r (MAX)

At bottom: T and mg oppose. Net upward = centripetal. T is MAXIMUM at the bottom.

18. Vertical Circle — Top

m T ↓ mg ↓ Top of circle T+mg=mv²/r → T MIN

At top: BOTH T and mg point toward center (downward). T is minimum. Min speed: v = √(rg).

19. Banked Road (No Friction)

θ car N (⊥ road) mg Nsinθ tanθ = v²/rg (ideal speed)

N tilted → horizontal Nsinθ provides centripetal force. Ncosθ balances mg.

20. Charge in Electric Field

→ E field +q F=qE mg +q → along E direction −q → opposite to E

Electric force F = qE. +q along E, −q against E. Add mg if particle has mass.

21. Two Charges — Coulomb Force

+q₁ +q₂ ←— repel —→ Same charges → repulsion Opposite → attraction F = kq₁q₂/r²

FBD of each charge separately. Each charge has a force ON it from the other charge.

22. Lorentz Force — Charge in B Field

B field: ⊙ out of page ⊙⊙ ⊙⊙ ⊙⊙⊙ +q v → F=qvB ↑ v→, B⊙ → F↑ (right-hand rule) F always ⊥ to v (no work done!)

Magnetic force ⊥ to velocity. Use right-hand rule: v along →, B out → F points up.

23. Current Wire in B Field

B field: ⊗ into page ⊗⊗⊗ wire I ↑ F ← I↑, B⊗ → F← (Fleming's LHR) F = BIL

Force on current conductor F = BIL. Direction from Fleming's Left Hand Rule.

24. Elevator — Accelerating Up

ELEVATOR a↑ Person N↑ mg↓ N = m(g+a) → Heavier!

N − mg = ma. N = m(g+a) > mg. Person feels heavier when elevator accelerates up.

25. Elevator — Accelerating Down

ELEVATOR a↓ Person N↑ mg↓ N = m(g−a) → Lighter!

mg − N = ma. N = m(g−a) < mg. If a = g → N = 0 → weightlessness!

26. Block + Spring System

Block N mg kx ← F_spring = kx (Hooke's Law)

Spring force F = kx, opposite to compression/stretch. 4 forces total on the block.

27. Tension Varies in Rope

Fixed Rope mass = M Block m T_top T_mid T_bot T_top > T_mid > T_bot

Top of rope supports more weight (rope below + block). T maximum at top, minimum at bottom.

05

Common Mistakes

❌ Missing Normal Force

Forgetting to draw N when block is on incline or any surface. N is perpendicular to the surface — not vertical on inclines!

✅ Ask: "Is the object touching a surface?" YES → Draw N perpendicular to it.

❌ Wrong Friction Direction

Drawing friction in the direction of motion. Friction ALWAYS opposes motion or tendency of motion.

✅ Ask: "Which way would it move without friction?" Draw friction OPPOSITE to that.

❌ Drawing "Force of Motion"

Adding an arrow in the direction of motion (velocity). There is NO "force of motion" — velocity is not a force!

✅ FBD has only real forces: Weight, Normal, Tension, Friction, Applied. Nothing else.

❌ Confusing Action-Reaction

Including forces the object exerts ON others in the object's own FBD. Newton's 3rd law pairs NEVER appear in the same FBD.

✅ FBD of A shows ONLY forces acting ON A. Forces A exerts on B → B's FBD, not A's.

❌ Not Resolving Forces on Incline

Using mg directly without resolving into components parallel and perpendicular to the incline surface.

✅ Tilt axes! x along incline, y perpendicular. Then: mgsinθ (along) and mgcosθ (perpendicular).

❌ Normal Force Pointing Vertically on Incline

Drawing N vertically upward when block is on an incline. N is always PERPENDICULAR to the surface, not vertical!

✅ Draw the surface first. N is always 90° away from that surface, pointing away from it.

❌ Forgetting to Isolate First

Drawing FBD of the whole setup and getting forces mixed up between different objects.

✅ ALWAYS isolate ONE body first. Draw it alone. Then add forces acting on IT only.

❌ Missing Tension in Connected Bodies

When two blocks are connected, tension must be drawn on EACH block separately as a force acting ON it.

✅ For each block, draw T pointing AWAY from block, along the string direction.
06

5 Solved Examples

Board Exam Strategy

"Always draw FBD first." Convert diagram → equation → answer. Skipping the FBD skips the marks.

Example 1 — Block on Rough Incline: Find acceleration ▼

Problem: A 5 kg block on 30° incline. μk = 0.3. Block slides down. Find acceleration.

Step 1 — Draw FBD

Forces: (a) mg = 50 N ↓, (b) N perpendicular to incline, (c) Kinetic friction f up the incline

Step 2 — Tilt Axes Along Incline

x-axis: along incline (positive = down), y-axis: perpendicular to incline

Step 3 — Write Equations
y-direction: N − mgcos30° = 0 → N = 5×10×(√3/2) = 43.3 N
Friction: f = μk × N = 0.3 × 43.3 = 13 N (up the incline)
x-direction: mgsin30° − f = ma → 25 − 13 = 5a
✓ Answer: a = 12/5 = 2.4 m/s² (down the incline)
Example 2 — Atwood Machine: Find tension and acceleration ▼

Problem: m₁ = 3 kg, m₂ = 5 kg connected over a pulley. Find a and T.

Step 1 — FBD of each mass

m₁: T (up), m₁g (down) | m₂: T (up), m₂g (down). Since m₂ > m₁, m₂ goes down.

Step 2 — Apply Newton's Second Law
For m₁ (goes up): T − m₁g = m₁a → T = m₁(g+a)
For m₂ (goes down): m₂g − T = m₂a → T = m₂(g−a)
Step 3 — Solve the System
m₁(g+a) = m₂(g−a) → 3(10+a) = 5(10−a) → 30+3a = 50−5a → 8a = 20
✓ a = 2.5 m/s² · T = 3×12.5 = 37.5 N
Example 3 — Elevator: Find apparent weight ▼

Problem: 60 kg person in elevator accelerating UP at 3 m/s². Find apparent weight.

Step 1 — FBD of Person

Forces: N (up from elevator floor), mg = 600 N (down). Net force upward = ma.

Step 2 — Apply F = ma
N − mg = ma (taking upward as positive)
N = m(g + a) = 60×(10 + 3) = 60 × 13 = 780 N
✓ Apparent weight = 780 N (feels like 78 kg instead of 60 kg — feels heavier!)

Bonus: If elevator accelerates DOWN at 3 m/s² → N = 60×7 = 420 N (feels only 42 kg!)

Example 4 — Conical Pendulum: Find angle and tension ▼

Problem: Conical pendulum L = 1 m, speed v = 2 m/s, mass m = 0.5 kg. Find θ and T.

Step 1 — FBD of Bob

Forces: T along string (upward + inward), mg = 5 N downward.

Step 2 — Resolve T into components
Vertical equilibrium: Tcosθ = mg = 5 N ... (1)
Centripetal (horizontal): Tsinθ = mv²/r = mv²/(Lsinθ) ... (2)
Step 3 — Divide equations (2)÷(1)
tanθ = v²/(gL) = 4/(10×1) = 0.4 → θ = arctan(0.4) ≈ 21.8°
T = mg/cosθ = 5/cos(21.8°) = 5/0.929 ≈ 5.38 N
✓ θ ≈ 21.8° · T ≈ 5.38 N
Example 5 — Two Blocks Horizontal: Find tension ▼

Problem: F = 30 N applied to block A (2 kg) connected to block B (3 kg) via string. Smooth surface. Find a and T.

Step 1 — FBD of Whole System (to find a)
Total mass = 2 + 3 = 5 kg. Net force = 30 N. a = 30/5 = 6 m/s²
Step 2 — FBD of Block B Alone (to find T)

Only horizontal force on B = Tension T (T pulls it forward)

T = m_B × a = 3 × 6 = 18 N
Step 3 — Verify with Block A
F − T = m_A × a → 30 − 18 = 2 × 6 = 12 ✓ Verified!
✓ a = 6 m/s² · T = 18 N
07

Teaching Tricks & Hacks

Teacher Script — Opening Hook

"Imagine you're in a tug-of-war with 3 friends pulling you in different directions. Before you can figure out who wins, you need to know exactly how hard each person is pulling. A Free Body Diagram is exactly that — a picture that shows every force pulling on YOU, so we can calculate what happens. Nothing more, nothing less."

🧠 Memory Shortcuts

  • W.A.N.T. = Weight, Applied, Normal, Tension (force checklist)
  • "Friction always fights" = opposes whatever the object wants to do
  • "N is always neat" = always ⊥ to the contact surface
  • "mg goes down, always down" = no exceptions, ever
  • "SIN goes along, COS goes cross" = mgsinθ along incline, mgcosθ perpendicular
  • "Isolate before you calculate" = draw FBD before any equation

✋ Gesture-Based Teaching

  • Pointing game: Point down = weight. Push up from below = normal. Pull string = tension.
  • Body as block: Stand up. Someone pushes (F). Ground pushes your feet (N). Gravity pulls (mg). Friction stops you sliding.
  • Book stack: 3 books stacked — pull middle one. Ask: what forces act on middle book ONLY?
  • String + eraser: Hold string with eraser attached. When still: T = mg. Move up: feel T increase!

🖊️ Board Drawing Techniques

  • Draw the OBJECT first (box/circle), then all arrows
  • Use different colors: Red = weight, Green = normal, Blue = tension, Orange = friction
  • Make arrows start from center of the object
  • Write force name at arrowhead, not at tail
  • For inclines, tilt your whole diagram — students find it much easier
  • Mark balanced cases: equal length opposite arrows = equilibrium

🎯 Student Thinking Process

  • Step 1: "Which object?" → Circle it mentally
  • Step 2: "Touching anything?" → N for each surface
  • Step 3: "Has mass?" → mg downward (always!)
  • Step 4: "Any strings?" → T away from object
  • Step 5: "Surface rough?" → Friction opposite motion
  • Step 6: "Any other force?" → Add it
  • Step 7: Write ΣF = ma equations!

📝 Exam Tips — Board & JEE

In Board Exams: Always label your FBD "FBD of block" or "FBD of m₁"
Show BOTH FBD AND equation for full marks
For inclines: always specify positive direction
1 mark for FBD + 2 marks for equation + 2 for answer
In JEE: Wrong FBD → Wrong equation → 0 marks
Spend 30 seconds on FBD first — always
For multi-body problems: draw SEPARATE FBD for each
Check: does number of unknowns = number of equations?
08

Rapid Revision Sheet

⚡ The 5-Second FBD Check

Weight (mg)
Normal (N)
Tension (T)
Friction (f)
Applied Force
Electric/Magnetic

Weight (mg)

↓ Always downward
mg = mass × 10 m/s²
Acts on EVERY object
Never changes direction
Even on inclines!

Normal (N)

⊥ to surface always
Away from surface
Only when touching
N = 0 in free fall
N = mgcosθ on incline

Tension (T)

Along string
Away from object
Same T throughout
(massless string)
T ≥ 0 always

Friction (f)

Opposes motion
Static: f ≤ μ_s N
Kinetic: f = μ_k N
μ_k < μ_s always
On rough surfaces only

Incline Rules

N = mgcosθ
Along: mgsinθ
Tilt your axes!
Friction opposes slide
Resolve mg always

Elevator Cases

a↑: N = m(g+a)
a↓: N = m(g−a)
a = g down: N = 0
Constant v: N = mg
Weightlessness: a = g

Vertical Circle

Bottom: T−mg = mv²/r
Top: T+mg = mv²/r
T minimum at TOP
T maximum at BOTTOM
Min v = √(rg)

Class 12 Forces

Electric: F = qE
+q along E direction
−q opposite to E
Magnetic: F = qvB
Always ⊥ to velocity

Atwood Machine

a = (m₂−m₁)g/(m₁+m₂)
T = 2m₁m₂g/(m₁+m₂)
Same T for both
Same acceleration
m₂ > m₁ → m₂ falls

When to Use FBD

Any force question
Any incline problem
Any pulley/string
Any circular motion
Any field (E or B)

"Physics without FBD is like solving mathematics without writing steps — you might get the answer, but you'll never get the marks."
— Master FBD. Master Physics. Master CBSE.

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