QUESTION:

A screw gauge has a least count of 0.01 mm, there are 50 divisions in its circular scale, then the pitch of the screw is…………

• A)     0.01 mm
• B)     0.25mm
• C)     0.5 mm
• D)     1.0 mm

   ANSWER: (C)

Least count is the least value that can be measured by a screw gauge.

As per question the least count of the screw gauge is 0.01 mm, total number of divisions on its circular scale is 50

 Pitch = Least count X total number of divisions in the circular scale

 Pitch of the screw = 0.01 mm X 50

  Pitch of the screw = 0.5 mm

EXAMPLE:

 

QUESTION-2