
QUESTION-1:
A screw gauge has a least count of 0.01 mm, there are 50 divisions in its circular scale, then the pitch of the screw is…………
- A) 0..01 mm
- B) 0.25mm
- C) 0.5 mm
- D) 1.0 mm
ANSWER: (C)
SOLUTION:
Least count is the least value that can be measured by a screw gauge.
PITCH OF THE SCREW:

LEAST COUNT:


As per question the least count of the screw gauge is 0.01 mm, total number of divisions on its circular scale is 50
Pitch = Least count X total number of divisions in the circular scale
Pitch of the screw = 0.01 mm X 50
Pitch of the screw = 0.5 mm

QUESTION-2
A 40 micro-farad capacitor is connected to a 200 V, 50 Hz ac supply. The rms value of current in the supply is nearly,
- A) 1.7 A
- B) 2.05 A
- C) 2.5 A
- D) 25.1 A
ANSWER-(C)
SOLUTION:
CAPACITIVE REACTANCE:
Capacitive reactance of a capacitor Is the effective resistance offered by the capacitor to the flow of current through it.

RMS VALUE OF CURRENT:


VARIATION OF CAPACITIVE REACTANCE WITH FREQUENCY:

GRAPHICAL REPRESENTATION:



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